When 6.5 g of Zn (0.1 mol) reacts with 7.3 g of HCl (0.2 mol), the theoretical yield of ZnCl₂ is (Zn + 2HCl → ZnCl₂; ZnCl₂=136 g/mol):

  • 13.6 g
  • 6.5 g
  • 7.3 g
  • 27.2 g
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