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Moles and Avogadro's Numbers

150 questions found

Practice Questions

One mole of helium atoms has a mass of

A. 1 g
B. 2 g
C. 4 g
D. 8 g

The atomic mass of helium is four grams per mole.

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For a fixed mass of any substance, the greatest number of moles is obtained when the molar mass is

A. Highest
B. Lowest
C. Equal to density
D. Equal to atomic number

Number of moles is inversely proportional to molar mass.

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Percentage yield = (0.45 ÷ 0.75) × 100 = 60%.

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The balanced equation is 3Fe + 4H₂O → Fe₃O₄ + 4H₂. Their sum is 12.

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Equal volumes of gases under identical conditions contain equal numbers of molecules according to

A. Boyle's law
B. Charles' law
C. Avogadro's law
D. Dalton's law

Avogadro's law relates gas volume directly with the number of molecules at constant temperature and pressure.

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The sample contains 0.25 mole of CO₂. Since one mole weighs 44 g, the mass is 11 g.

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Half a mole of CO₂ occupies 11.2 dm³ at STP.

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The mass of a single sulfuric acid molecule is calculated by dividing 98 g by

A. Atomic number
B. Molecular volume
C. Avogadro's number
D. Equivalent weight

The molar mass divided by Avogadro's number gives the mass of one molecule.

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Complete oxidation of 64 g SO₂ according to 2SO₂ + O₂ → 2SO₃ forms

A. 0.5 mole SO₃
B. 1 mole SO₃
C. 2 moles SO₃
D. 3 moles SO₃

Sixty-four grams of SO₂ equal one mole, producing one mole of SO₃.

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The relationship between one carbon-12 atom and one atomic mass unit is

A. Equal masses
B. Carbon atom is twelve times heavier
C. Atomic mass unit is twelve times heavier
D. Both have identical masses

One atomic mass unit is defined as one-twelfth the mass of a carbon-12 atom.

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Actual yield equals 80% of theoretical yield. Therefore, 0.80 × 5 = 4 moles.

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One mole of methane contains protons equal to

A. 6.022 × 10²³
B. 3.011 × 10²⁴
C. 6.022 × 10²⁴
D. 1.204 × 10²⁵

One methane molecule contains ten protons. Thus, one mole contains 10 × Avogadro's number of protons.

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The balanced equation directly provides the ratio.

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Avogadro’s constant represents

A. Number of atoms in one gram
B. Number of particles in one mole
C. Number of electrons in hydrogen
D. Number of molecules in one litre

One mole always contains 6.022 × 10²³ elementary particles.

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During the reaction N₂ + 2O₂ → 2NO₂, complete reaction of 0.5 mole nitrogen produces

A. 0.5 mole NO₂
B. 2 moles NO₂
C. 1 mole NO₂
D. 0.25 mole NO₂

One mole of nitrogen produces two moles of nitrogen dioxide. Therefore, 0.5 mole yields one mole.

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At STP, two moles of an ideal gas occupy

A. 11.2 dm³
B. 22.4 dm³
C. 33.6 dm³
D. 44.8 dm³

One mole occupies 22.4 dm³ at STP, so two moles occupy 44.8 dm³.

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During the reaction 2Mg + O₂ → 2MgO, complete oxidation of 48 g magnesium forms

A. 40 g MgO
B. 80 g MgO
C. 120 g MgO
D. 160 g MgO

Forty-eight grams of magnesium equal two moles, producing two moles of MgO. The mass becomes 80 g.

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One mole of ammonia contains hydrogen atoms equal to

A. 1 mole
B. 2 moles
C. 3 moles
D. 4 moles

Each NH₃ molecule contains three hydrogen atoms; therefore one mole of NH₃ contains three moles of hydrogen atoms.

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A sample containing 0.5 mole of a compound possesses

A. 3.011 × 10²³ molecules
B. 6.022 × 10²³ molecules
C. 1.204 × 10²⁴ molecules
D. 1.505 × 10²³ molecules

Half a mole contains half of Avogadro's number of molecules.

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