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Limiting and Excess Reactants

74 questions found

Practice Questions

N₂ is the limiting reactant and is completely consumed.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

HCl is limiting. CaCl₂ formed = 0.5 mol. Mass = 55.5 g.

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Jul 2, 2026

71. The theoretical yield of a product is calculated based on the

A. Amount of the excess reactant
B. Average mass of reactants
C. Amount of the limiting reactant
D. Amount of catalyst

The limiting reactant determines the maximum product obtainable.

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Jul 2, 2026

Stoichiometric mixture. Titanium formed = 1 mol = 48 g.

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Carbon is limiting. CH₄ = 1.5 mol. Mass = 24 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

74. The mole ratio from the balanced equation is used to calculate the amount of excess reactant consumed by the

A. Limiting reactant
B. Product formed
C. Catalyst present
D. Initial mixture volume

The limiting reactant determines how much of the excess reactant is used.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Stoichiometric mixture. H₂ produced = 0.3 mol. Volume = 6.72 dm³.

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Stoichiometric mixture. Na₂CO₃ = 1 mol. Mass = 106 g.

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AgNO₃ = 0.2 mol and Cu = 0.1 mol. Stoichiometric mixture. Ag formed = 0.2 mol = 21.6 g.

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Jul 2, 2026

O₂ is limiting. P₂O₅ formed = 0.8 mol.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

51. The primary purpose of using an excess of one reactant in a chemical process is often to

A. Increase the activation energy
B. Ensure the complete consumption of a more valuable or limiting reactant
C. Decrease the temperature of the reaction
D. Increase the purity of the product

An inexpensive reactant is often used in excess so that the valuable reactant is completely consumed.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

One mole X requires 3 mol Y. Only 2 mol Y are available.

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Jul 2, 2026

Al = 0.667 mol and is limiting. H₂ produced = 1 mol. Volume = 22.4 dm³.

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Jul 2, 2026

SO₂ is limiting. SO₃ formed = 2 mol. Mass = 160 g.

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Both react stoichiometrically. CO₂ formed = 0.5 mol. Volume = 11.2 dm³.

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Fe = 0.5 mol (limiting). FeS formed = 0.5 mol. Mass = 44 g.

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Jul 2, 2026

Stoichiometric mixture. P₄O₁₀ = 0.5 mol. Mass = 142 g.

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10 mol A require 20 mol B. Only 10 mol B are available, so B is limiting.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

BaCl₂ is limiting. BaSO₄ formed = 0.3 mol. Mass = 69.9 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026
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