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Moles and Avogadro’s Numbers

120 questions found

Practice Questions

Twenty-eight grams of iron react with twenty grams sulfur. The limiting reactant is

A. Sulfur
B. Iron
C. Both react completely
D. Neither reacts

Iron provides only 0.5 mole while sulfur provides 0.625 mole. Iron is present in the smaller stoichiometric amount.

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Twelve moles of water react with one mole Al₄C₃. Mass = 12 × 18 = 216 g.

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One-quarter mole KMnO₄ contains oxygen atoms equal to

A. 0.25 mole
B. 0.50 mole
C. 1 mole
D. 2 moles

Each mole KMnO₄ contains four moles oxygen atoms. Therefore, 0.25 mole contains one mole oxygen atoms.

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Thermal decomposition of one mole Pb(NO₃)₂ leaves residue weighing

A. 207 g
B. 223 g
C. 239 g
D. 446 g

One mole Pb(NO₃)₂ forms one mole PbO whose molar mass is 223 g.

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Oxygen gas weighing 1.6 g contains molecules equal to

A. 3.011 × 10²²
B. 6.022 × 10²²
C. 3.011 × 10²³
D. 6.022 × 10²³

1.6 g oxygen equals 0.05 mole. Therefore, the number of molecules equals 0.05 × Avogadro's number.

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Twenty-five grams equal 0.25 mole CaCO₃. The same amount of CO₂ occupies 5.6 dm³ at STP.

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Moles of CS₂ = 19/76 = 0.25 mol. According to the equation, 1 mol CS₂ produces 2 mol SO₂. Therefore, 0.25 mol CS₂ forms 0.5 mol SO₂. Mass = 0.5 × 64 = 32 g.

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The total number of ions in 0.1 moles of aluminium sulphate, Al₂(SO₄)₃, is

A. 6.022 × 10²³
B. 6.022 × 10²²
C. 3.011 × 10²³
D. 3.011 × 10²²

One formula unit produces 5 ions (2 Al³⁺ + 3 SO₄²⁻). Therefore, 0.1 mol gives 0.5 mol ions = 3.011 × 10²³ ions.

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4.6 g Na = 0.2 mol. From the equation, 2 mol Na produce 1 mol H₂. Hence 0.2 mol Na produces 0.1 mol H₂.

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Equal coefficients indicate equal numbers of moles.

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One mole of an organic compound contains six moles of carbon atoms. The compound may be

A. CH₄
B. C₂H₅OH
C. C₆H₆
D. C₃H₆O

Benzene contains six carbon atoms per molecule.

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Complete combustion of 16 g methane requires oxygen weighing

A. 16 g
B. 32 g
C. 48 g
D. 64 g

One mole methane requires two moles oxygen. Therefore, oxygen required is 64 g.

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Complete hydrolysis of one mole Al₄C₃ requires water weighing

A. 54 g
B. 108 g
C. 144 g
D. 216 g

Twelve moles of water react with one mole Al₄C₃. Twelve × 18 = 216 g.

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Molecular formula becomes C₆H₁₂O₆, containing twelve hydrogen atoms.

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Gas volumes follow mole ratios. Hydrogen volume is three times nitrogen volume.

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Complete combustion of 0.25 mole pentane forms total products equal to

A. 1.25 moles
B. 2.75 moles
C. 5.50 moles
D. 11 moles

One mole pentane forms eleven moles of gaseous products. One-quarter mole forms 2.75 moles.

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Nineteen grams correspond to 0.25 mole CS₂. This produces 0.5 mole SO₂ having a mass of 32 g.

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One-tenth mole of aluminium sulfate, Al₂(SO₄)₃, contains total ions equal to

A. 6.022 × 10²²
B. 3.011 × 10²³
C. 6.022 × 10²³
D. 1.204 × 10²⁴

One formula unit produces five ions. Therefore, 0.1 mole gives 0.5 mole of ions, equal to 3.011 × 10²³ ions.

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4.6 g Na equals 0.2 mole. According to the equation, 2 moles Na produce 1 mole H₂. Thus, 0.2 mole Na produces 0.1 mole H₂.

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Jul 2, 2026
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