Na = 2 mol, H₂O = 3 mol. Na is limiting. H₂ = 1 mol = 2 g.
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34. A reaction between 2 moles of C₂H₄ and 2 moles of O₂ proceeds via C₂H₄ + 3O₂ → 2CO₂ + 2H₂O. The number of moles of water formed is
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36. During the combustion of 20 g of CH₄ with 20 g of O₂ (CH₄ + 2O₂ → CO₂ + 2H₂O), the limiting reactant is