Al = 1 mol (limiting). Cr produced = 1 mol = 52 g.
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36. During the combustion of 20 g of CH₄ with 20 g of O₂ (CH₄ + 2O₂ → CO₂ + 2H₂O), the limiting reactant is
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38. The amount of excess reactant remaining is calculated by subtracting the amount consumed from the initial amount. The amount consumed is determined from the stoichiometric ratio and the amount of the
