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Chemistry NMDCAT MCQs Moles and Avogadro's Numbers
nmdcat.online July 2, 2026

A sample of calcium carbonate (CaCO₃) weighing 50 g is strongly heated. CaCO₃ → CaO + CO₂. The mass of solid residue left is

A. 50 g
B. 28 g
✓
C. 44 g
D. 22 g

📝 Explanation

50 g CaCO₃ = 0.5 mole. It forms 0.5 mole CaO. Mass = 0.5 × 56 = 28 g.

📖 Additional Information

  • 50 g
  • 28 g
  • 44 g
  • 22 g

50 g CaCO₃ = 0.5 mole. It forms 0.5 mole CaO. Mass = 0.5 × 56 = 28 g.

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