nmdcat.online
Chemistry NMDCAT MCQs Moles and Avogadro's Numbers Moles and Avogadro’s Numbers
nmdcat.online July 2, 2026

Complete combustion of 16 g methane requires oxygen having a mass of

A. 16 g
B. 32 g
C. 64 g
✓
D. 48 g

📝 Explanation

16 g CH₄ = 1 mol. One mole methane requires two moles oxygen. Mass = 2 × 32 = 64 g.

📖 Additional Information

  • 16 g
  • 32 g
  • 64 g
  • 48 g

16 g CH₄ = 1 mol. One mole methane requires two moles oxygen. Mass = 2 × 32 = 64 g.

🔗 Share This Question

Facebook Twitter LinkedIn WhatsApp

🧭 Navigate Questions

Previous Question

One mole of an organic compound contains six moles of carbon atoms. The compound is

Next Question

One mole of Al₄C₃ reacts completely with water. The mass of water required is

Back to All Questions

🔗 Related MCQs

Among the following statements, the most appropriate explanation for expressing chemical amounts in moles is
July 13, 2026
Regarding representative particles, one mole of calcium ions contains
July 13, 2026
During the reaction N₂ + 3H₂ → 2NH₃, complete reaction of 44.8 L of nitrogen gas at STP produces
July 13, 2026
Under standard conditions, 89.6 L of oxygen gas corresponds to
July 13, 2026
Regarding the balanced equation 2K + 2H₂O → 2KOH + H₂, complete reaction of 8 moles of potassium produces
July 13, 2026

Categories

View all →