nmdcat.online
Chemistry NMDCAT MCQs Moles and Avogadro's Numbers Moles and Avogadro’s Numbers
nmdcat.online July 13, 2026

Concerning the reaction CaCO₃ → CaO + CO₂, decomposition of 200 g of calcium carbonate produces approximately

A. 1 mole of CO₂
B. 2 moles of CO₂
✓
C. 3 moles of CO₂
D. 4 moles of CO₂

📝 Explanation

Molar mass of CaCO₃ = 100 g mol⁻¹. Thus, 200 g = 2 moles, producing 2 moles of CO₂ because the mole ratio is 1 : 1. Concept tested: Mass-to-mole conversion using balanced equations.

📖 Additional Information

  • 1 mole of CO₂
  • 2 moles of CO₂
  • 3 moles of CO₂
  • 4 moles of CO₂

Molar mass of CaCO₃ = 100 g mol⁻¹. Thus, 200 g = 2 moles, producing 2 moles of CO₂ because the mole ratio is 1 : 1. Concept tested: Mass-to-mole conversion using balanced equations.

🔗 Share This Question

Facebook Twitter LinkedIn WhatsApp

🧭 Navigate Questions

Previous Question

During a stoichiometric calculation, 2 moles of oxygen molecules contain

Next Question

During the combustion reaction 2H₂ + O₂ → 2H₂O, complete reaction of 44.8 L of hydrogen gas at STP requires

Back to All Questions

🔗 Related MCQs

Among the following statements, the most appropriate explanation for expressing chemical amounts in moles is
July 13, 2026
Regarding representative particles, one mole of calcium ions contains
July 13, 2026
During the reaction N₂ + 3H₂ → 2NH₃, complete reaction of 44.8 L of nitrogen gas at STP produces
July 13, 2026
Under standard conditions, 89.6 L of oxygen gas corresponds to
July 13, 2026
Regarding the balanced equation 2K + 2H₂O → 2KOH + H₂, complete reaction of 8 moles of potassium produces
July 13, 2026

Categories

View all →