Chemistry NMDCAT MCQs Moles and Avogadro's Numbers Moles and Avogadro’s Numbers
nmdcat.online July 13, 2026

During the reaction 2Na + 2H₂O → 2NaOH + H₂, complete reaction of 9.2 g of sodium produces

A. 0.10 mole of H₂
B. 0.20 mole of H₂
C. 0.30 mole of H₂
D. 0.40 mole of H₂

📝 Explanation

Molar mass of Na = 23 g mol⁻¹. Therefore, 9.2 g Na = 0.40 mole. According to the balanced equation, 2 moles of Na produce 1 mole of H₂. Thus, 0.40 mole Na produces 0.20 mole H₂. Concept tested: Mass-to-mole stoichiometric calculation.

📖 Additional Information

  • 0.10 mole of H₂
  • 0.20 mole of H₂
  • 0.30 mole of H₂
  • 0.40 mole of H₂

Molar mass of Na = 23 g mol⁻¹. Therefore, 9.2 g Na = 0.40 mole. According to the balanced equation, 2 moles of Na produce 1 mole of H₂. Thus, 0.40 mole Na produces 0.20 mole H₂. Concept tested: Mass-to-mole stoichiometric calculation.

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