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Chemistry NMDCAT MCQs Moles and Avogadro's Numbers
nmdcat.online July 2, 2026

In the reaction 2KClO₃ → 2KCl + 3O₂, the mass of potassium chlorate required to produce 9.6 g of oxygen is

A. 12.25 g
B. 24.5 g
✓
C. 36.75 g
D. 49 g

📝 Explanation

Moles of O₂ = 9.6 ÷ 32 = 0.3 mole. Required KClO₃ = 0.3 × 2/3 = 0.2 mole. Mass = 0.2 × 122.5 = 24.5 g.

📖 Additional Information

  • 12.25 g
  • 24.5 g
  • 36.75 g
  • 49 g

Moles of O₂ = 9.6 ÷ 32 = 0.3 mole. Required KClO₃ = 0.3 × 2/3 = 0.2 mole. Mass = 0.2 × 122.5 = 24.5 g.

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