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nmdcat.online June 27, 2026

The use of Benedict’s test on a solution of sucrose yields a negative result (no color change) because sucrose

A. Is a monosaccharide, not a disaccharide
B. Has a free aldehyde group that is locked in the furanose ring
C. Lacks a free anomeric carbon capable of reducing Cu²⁺, as both are involved in the glycosidic bond
✓
D. Is a non-reducing sugar that can only be detected by the iodine test

📝 Explanation

The glycosidic bond in sucrose is formed between the anomeric carbon (C1) of glucose and the anomeric carbon (C2) of fructose. Since neither carbonyl group is free to open into an aldehyde or ketone form, sucrose cannot reduce Cu²⁺ and is thus a non-reducing sugar.

📖 Additional Information

  • Is a monosaccharide, not a disaccharide
  • Has a free aldehyde group that is locked in the furanose ring
  • Lacks a free anomeric carbon capable of reducing Cu²⁺, as both are involved in the glycosidic bond
  • Is a non-reducing sugar that can only be detected by the iodine test

The glycosidic bond in sucrose is formed between the anomeric carbon (C1) of glucose and the anomeric carbon (C2) of fructose. Since neither carbonyl group is free to open into an aldehyde or ketone form, sucrose cannot reduce Cu²⁺ and is thus a non-reducing sugar.

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