Moles of O₂ = 64 g ÷ 32 g/mol = 2.0 moles. At STP, molar volume is 22.4 dm³. Therefore, volume = 2.0 × 22.4 = 44.8 dm³.
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In the complete combustion of methane, CH₄ + 2O₂ → CO₂ + 2H₂O, the volume of oxygen required at STP to completely burn 2.5 moles of methane is
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The number of representative particles (molecules) present in 88 g of carbon dioxide (CO₂) is (Molar mass of CO₂ = 44 g/mol)
