Practice Questions

One mole pentane forms eleven moles of gaseous products. One-quarter mole forms 2.75 moles.

Gas volumes follow mole ratios. Hydrogen volume is three times nitrogen volume.

Molecular formula becomes C₆H₁₂O₆, containing twelve hydrogen atoms.

Twelve moles of water react with one mole Al₄C₃. Twelve × 18 = 216 g.

One mole methane requires two moles oxygen. Therefore, oxygen required is 64 g.

Benzene contains six carbon atoms per molecule.

Equal coefficients indicate equal numbers of moles.

Ten grams correspond to 0.1 mole CaCO₃, producing 0.1 mole CO₂ occupying 2.24 dm³ at STP.

The sample contains 0.25 mole urea. With molar mass 60 g mol⁻¹, the mass equals 15 g.

One mole H₂S produces 1.5 moles sulfur. The mass becomes 1.5 × 32 = 48 g.