Practice Questions

The primary function of an isoenzyme, such as lactate dehydrogenase (LDH), in a physiological context is to

A. Catalyze the same reaction but under different kinetic properties or regulatory conditions in different tissues
B. Bind to the same substrate to form different products depending on the organ
C. Act as a competitive inhibitor for the original enzyme
D. Combine several different metabolic pathways into a single rate-limiting step

Isoenzymes are multiple forms of an enzyme that catalyze the same reaction but differ in kinetic properties, allowing for tissue-specific metabolic tailoring.

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Among the following statements, the one that correctly links an enzyme to its function is

A. DNA ligase: unwinding of the DNA double helix
B. Helicase: sealing of nicks between Okazaki fragments
C. DNA polymerase: addition of nucleotides using a DNA template
D. Ribonuclease: degradation of double-stranded genomic DNA

DNA polymerase catalyzes the template-directed addition of deoxynucleotides to a growing DNA chain.

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An enzyme that exhibits absolute specificity will catalyze a reaction with

A. All substrate molecules that possess a similar functional group
B. A single, specific substrate molecule
C. Only those substrates that have a double bond in their structure
D. Substrates of a specific optical isomer but not the other

Absolute specificity means the enzyme acts on only one specific substrate, unlike group specificity which acts on substrates with a common functional group.

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During a reaction catalyzed by hexokinase, the binding of glucose induces a conformational change that places the ATP molecule optimally for phosphate transfer. This illustrates the

A. Lock and Key model
B. Induced Fit model
C. Competitive inhibition mechanism
D. Allosteric activation mechanism

The induced fit model is exemplified by conformational changes in hexokinase upon glucose binding, which correctly orient ATP for catalysis.

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The specificity of an enzyme like glucokinase for glucose over other hexoses is best explained by the

A. Unique peptide sequence in the enzyme's non-catalytic domain
B. Precise three-dimensional shape and chemical environment of the active site
C. Regulatory effects of coenzyme NAD+ on the enzyme's structure
D. Enzyme's ability to phosphorylate only six-carbon sugars

Enzyme specificity arises from the unique 3D structure of the active site, which contains amino acid R-groups positioned to form interactions only with a specific substrate.

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The protein portion alone is the inactive apoenzyme, which requires a non-protein cofactor to form the complete, active holoenzyme.

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A decrease in the activation energy of a reaction in the presence of an enzyme results in

A. An increase in the number of substrate molecules reaching the transition state
B. A permanent change in the enzyme's primary structure
C. The reaction becoming endergonic instead of exergonic
D. A decrease in the total free energy released by the reaction

By lowering the activation energy, enzymes allow a much larger proportion of substrate molecules to reach the transition state at a given temperature, increasing the reaction rate.

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A key distinguishing characteristic of enzymes compared to non-biological catalysts is their

A. Ability to alter the equilibrium constant of a reaction
B. Capacity to catalyze a wide range of structurally unrelated reactions
C. Remarkable substrate specificity and susceptibility to regulation
D. Requirement for extremely high temperatures and pressures to function

Unlike inorganic catalysts, enzymes are highly specific and their activity is finely regulated by cellular mechanisms like allosteric control.

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In the context of enzyme kinetics, the Michaelis constant (Km) is numerically equal to the

A. Maximum velocity the enzyme can achieve
B. Substrate concentration at which the reaction velocity is half of Vmax
C. Enzyme concentration required for half-maximal activity
D. Turnover number of the enzyme

Km is a measure of an enzyme's affinity for its substrate, defined as the substrate concentration at which the reaction rate is one-half of the maximum velocity (Vmax).

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A graph of reaction rate versus substrate concentration for an enzyme-catalyzed reaction shows a hyperbolic curve because

A. Enzyme molecules become denatured at high substrate concentrations
B. Substrate molecules inhibit the reaction after a certain point
C. The enzyme becomes saturated, and all active sites are occupied
D. The activation energy increases exponentially with substrate concentration

At high substrate concentrations, all enzyme active sites are occupied. The reaction velocity reaches a maximum (Vmax), and further substrate addition cannot increase the rate.

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