nmdcat.online
Chemistry NMDCAT MCQs Limiting and Excess Reactants
nmdcat.online July 2, 2026

39. In the reaction Ca + 2H₂O → Ca(OH)₂ + H₂, 20 g of calcium and 36 g of water are reacted. The mass of excess reactant remaining is (Ca = 40, O = 16, H = 1)

A. 4 g Ca
B. 18 g H₂O
✓
C. 20 g H₂O
D. 8 g H₂O

📝 Explanation

Ca = 0.5 mol, H₂O = 2 mol. Water left = 1 mol = 18 g.

📖 Additional Information

  • 4 g Ca
  • 18 g H₂O
  • 20 g H₂O
  • 8 g H₂O

Ca = 0.5 mol, H₂O = 2 mol. Water left = 1 mol = 18 g.

🔗 Share This Question

Facebook Twitter LinkedIn WhatsApp

🧭 Navigate Questions

Previous Question

38. The amount of excess reactant remaining is calculated by subtracting the amount consumed from the initial amount. The amount consumed is determined from the stoichiometric ratio and the amount of the

Next Question

40. For the reaction 2KClO₃ → 2KCl + 3O₂, 245 g of KClO₃ is decomposed. The maximum volume of O₂ at STP is

Back to All Questions

🔗 Related MCQs

Among the following statements, the most appropriate explanation for expressing chemical amounts in moles is
July 13, 2026
Regarding representative particles, one mole of calcium ions contains
July 13, 2026
During the reaction N₂ + 3H₂ → 2NH₃, complete reaction of 44.8 L of nitrogen gas at STP produces
July 13, 2026
Under standard conditions, 89.6 L of oxygen gas corresponds to
July 13, 2026
Regarding the balanced equation 2K + 2H₂O → 2KOH + H₂, complete reaction of 8 moles of potassium produces
July 13, 2026

Categories

View all →