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Chemistry NMDCAT MCQs Moles and Avogadro's Numbers
nmdcat.online July 2, 2026

In the reaction 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O, the mass of sodium hydroxide required to neutralize 49 g of sulphuric acid is

A. 20 g
B. 40 g
✓
C. 80 g
D. 60 g

📝 Explanation

49 g H₂SO₄ = 0.5 mole. NaOH:H₂SO₄ = 2:1. Therefore, NaOH required = 1 mole = 40 g.

📖 Additional Information

  • 20 g
  • 40 g
  • 80 g
  • 60 g

49 g H₂SO₄ = 0.5 mole. NaOH:H₂SO₄ = 2:1. Therefore, NaOH required = 1 mole = 40 g.

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