nmdcat.online
Chemistry NMDCAT MCQs Moles and Avogadro's Numbers
nmdcat.online July 2, 2026

The number of molecules in 1 dm³ of an ideal gas at STP is approximately

A. 6.022 × 10²³
B. 2.69 × 10²²
✓
C. 1.81 × 10²⁴
D. 3.01 × 10²²

📝 Explanation

One mole occupies 22.4 dm³. Therefore, molecules in 1 dm³ = (6.022 × 10²³) ÷ 22.4 ≈ 2.69 × 10²².

📖 Additional Information

  • 6.022 × 10²³
  • 2.69 × 10²²
  • 1.81 × 10²⁴
  • 3.01 × 10²²

One mole occupies 22.4 dm³. Therefore, molecules in 1 dm³ = (6.022 × 10²³) ÷ 22.4 ≈ 2.69 × 10²².

🔗 Share This Question

Facebook Twitter LinkedIn WhatsApp

🧭 Navigate Questions

Previous Question

A sample of a pure element weighing 0.64 g contains 6.022 × 10²¹ atoms. The atomic mass of the element is

Next Question

In the reaction 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O, the mass of sodium hydroxide required to neutralize 49 g of sulphuric acid is

Back to All Questions

🔗 Related MCQs

Among the following statements, the most appropriate explanation for expressing chemical amounts in moles is
July 13, 2026
Regarding representative particles, one mole of calcium ions contains
July 13, 2026
During the reaction N₂ + 3H₂ → 2NH₃, complete reaction of 44.8 L of nitrogen gas at STP produces
July 13, 2026
Under standard conditions, 89.6 L of oxygen gas corresponds to
July 13, 2026
Regarding the balanced equation 2K + 2H₂O → 2KOH + H₂, complete reaction of 8 moles of potassium produces
July 13, 2026

Categories

View all →