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Practice Questions

21. The primary reason why a purine base cannot pair with another purine base inside a stable DNA double helix is that such an orientation would

A. Break the phosphodiester bonds
B. Cause a local distortion that widens the helix beyond 2 nanometers
C. Prevent the formation of any hydrogen bonds
D. Force the DNA to become a single-stranded RNA

Purines are double-ringed; pairing two purines would exceed the 2 nm diameter, while pairing two pyrimidines would make the helix too narrow.

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20. The hydrogen bonds that maintain the complementary base pairing of the DNA double helix are situated

A. On the very outside of the sugar-phosphate ribbon
B. Between the inward-facing nitrogenous bases of opposing strands
C. Connecting the 3' and 5' carbon locations of adjacent nucleotides
D. Linking histone proteins to the chromosome core

The hydrophilic sugar-phosphate backbones face the aqueous exterior, while the nitrogenous bases point inward to hide from water and form pairs.

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19. The biochemical definition of a gene as a segment of DNA that codes for a single polypeptide chain corresponds historically to the

A. One gene-one enzyme hypothesis
B. Fluid mosaic model
C. Central dogma of molecular biology
D. Cell theory

Refined by Beadle and Tatum, and later updated to "one gene-one polypeptide," this concept binds a genetic locus to a single protein product.

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18. The major and minor grooves observed along the exterior surface of the DNA double helix are structurally caused by

A. The presence of modified ribose sugars
B. The asymmetric attachment of base pairs to the sugar-phosphate backbones
C. Spontaneous strand breaks in the phosphate chain
D. The attachment of regulatory histone proteins

The glycosidic bonds do not project directly opposite one another, making the spaces between the backbones unequal around the cylinder.

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If A=30%, then T=30%, totaling 60%. The remaining 40% is split equally between Guanine (20%) and Cytosine (20%).

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16. The dynamic force that stabilizes the double helix by stacking the hydrophobic nitrogenous bases on top of one another belongs to

A. Covalent interactions
B. Hydrophobic interactions and van der Waals forces
C. Electrostatic ionic bridges
D. Disulfide linkages

While hydrogen bonds hold the pairs together horizontally, vertical base-stacking interactions insulate the hydrophobic bases from water.

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15. The chemical group located specifically at the 3′ terminus of a functional DNA strand is a

A. Phosphate group
B. Free hydroxyl group (-OH)
C. Methyl group
D. Ketone group

The 3' end of a nucleic acid strand terminates at the third carbon of the sugar ring, which carries a free hydroxyl group.

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14. The functional product coded by a structural gene during the process of gene expression is directly a

A. Polopolysaccharide chain
B. Polypeptide chain
C. Phospholipid bilayer
D. Steroid hormone molecule

Structural genes carry the specific nucleotide blueprints required to assemble amino acids into a polypeptide chain on a ribosome.

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13. The nitrogenous bases that possess a single-ring structure and are classified as pyrimidines in DNA are

A. Adenine and Guanine
B. Cytosine and Thymine
C. Thymine and Uracil
D. Adenine and Cytosine

Cytosine and thymine are single-ring pyrimidines, whereas adenine and guanine are double-ring purines.

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A codon is a triplet of bases that specifies a particular amino acid or a stop signal during protein translation.

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11. The vertical distance covered by one complete turn of the standard B-DNA double helix is

A. 0.34 nanometers
B. 2.0 nanometers
C. 3.4 nanometers
D. 20 nanometers

One complete helical turn spans a longitudinal length of 3.4 nm (34 A˚) and contains approximately 10 base pairs.

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10. In a double-stranded DNA molecule, the base-pairing pattern always obeys Chargaff’s rules, which state that the total amount of

A. Adenine equals cytosine
B. Purines equals pyrimidines
C. Thymine equals guanine
D. Uracil equals thymine

Chargaff’s rules dictate that [A]=[T] and [G]=[C]; therefore, the sum of purines (A+G) must equal the sum of pyrimidines (T+C).

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9. The scientific data that directly provided Watson and Crick with the structural dimensions and helical nature of DNA was derived from

A. Protein sequencing
B. X-ray diffraction images
C. Paper chromatography
D. Electron microscopy

Rosalind Franklin’s famous "Photo 51" obtained via X-ray crystallography revealed the helical configuration and dimensions of the DNA molecule.

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8. The chemical linkage that holds the sugar-phosphate backbone of a single DNA strand together is the

A. Hydrogen bond
B. Phosphodiester bond
C. Peptide bond
D. Glycosidic bond

Phosphodiester bonds covalently link the 3' carbon of one deoxyribose sugar to the 5' carbon of the adjacent sugar via a phosphate group.

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7. The total diameter of the standard B-form DNA double helix as determined by Watson and Crick is exactly

A. 1 nanometer
B. 2 nanometers
C. 3.4 nanometers
D. 0.34 nanometers

The double helix maintains a constant width of 2 nm (20 A˚) because a double-ringed purine always pairs with a single-ringed pyrimidine.

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Adenine (a purine) always pairs with thymine (a pyrimidine) using two hydrogen bonds in standard Watson-Crick base pairing.

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4. The chemical group located specifically at the 5′ terminus of a single DNA strand is a

A. Hydroxyl group
B. Phosphate group
C. Carboxyl group
D. Amino group

The 5' end of a DNA or RNA strand terminates in a phosphate group attached to the 5' carbon of the pentose sugar.

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A gene is the fundamental structural and functional unit of heredity, consisting of a nucleotide sequence that carries the code for a protein.

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Guanine pairs with cytosine via three hydrogen bonds, creating a more thermally stable bond than the adenine-thymine pair.

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