MCQs

One mole X requires 3 mol Y. Only 2 mol Y are available.

O₂ is limiting. P₂O₅ formed = 0.8 mol.

Stoichiometric mixture. Na₂CO₃ = 1 mol. Mass = 106 g.

O₂ is limiting. CO₂ = 3.2 mol. Volume = 71.68 dm³.

Stoichiometry is based on these fundamental chemical laws.

Potassium is limiting. KOH formed = 1 mol. Mass = 56 g.

Na₂CO₃ is limiting. CO₂ formed = 0.5 mol. Mass = 22 g.

Stoichiometric mixture. SO₂ = 1 mol. Mass = 64 g.

Stoichiometric coefficients always represent mole ratios.

0.2 mol Pb(NO₃)₂ produces 0.5 mol gases. Volume = 11.2 dm³.

BaCl₂ is limiting. BaSO₄ formed = 0.3 mol. Mass = 69.9 g.

10 mol A require 20 mol B. Only 10 mol B are available, so B is limiting.

Stoichiometric mixture. P₄O₁₀ = 0.5 mol. Mass = 142 g.

Fe = 0.5 mol (limiting). FeS formed = 0.5 mol. Mass = 44 g.

Both react stoichiometrically. CO₂ formed = 0.5 mol. Volume = 11.2 dm³.

Al = 0.667 mol and is limiting. H₂ produced = 1 mol. Volume = 22.4 dm³.

An inexpensive reactant is often used in excess so that the valuable reactant is completely consumed.

AgNO₃ = 0.2 mol and Cu = 0.1 mol. Stoichiometric mixture. Ag formed = 0.2 mol = 21.6 g.

2 mol butane require 13 mol O₂, exactly the amount available.