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N₂ = 0.5 mol. H₂ required = 1.5 mol but available = 4 mol. Excess H₂ = 2.5 mol = 5 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

ZnS ≈ 1 mol and O₂ = 1.5 mol. Stoichiometric mixture. ZnO = 1 mol = 81 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

46. The term “excess reagent” implies that after the reaction is complete, some amount of this reactant

A. Is completely converted to product
B. Remains unreacted in the reaction mixture
C. Acts as the solvent for the reaction
D. Is the limiting factor for the reaction rate

An excess reactant is supplied in greater quantity than required and remains after the reaction.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

NH₃ = 2 mol, O₂ = 1.5 mol. O₂ limits. NO = 1.2 mol. Mass = 1.2 × 30 = 36 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Stoichiometric mixture. Cl₂ produced = 1 mol = 71 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

NO = 2 mol and O₂ = 1 mol. Stoichiometric mixture. NO₂ formed = 2 mol.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

42. A limiting reactant problem fundamentally involves a comparison of the

A. Molecular weights of all species
B. Mole ratio of reactants available to the mole ratio required by the balanced equation
C. Physical states of the reactants
D. Total mass of the reaction mixture

Limiting reactants are identified by comparing available and required mole ratios.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Carbon is limiting. Si = 1.5 mol. Mass = 1.5 × 28 = 42 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

245 g = 2 mol KClO₃. O₂ = 3 mol. Volume = 3 × 22.4 = 67.2 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Ca = 0.5 mol, H₂O = 2 mol. Water left = 1 mol = 18 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

The limiting reactant determines how much of the excess reactant is consumed.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Al = 1 mol (limiting). Cr produced = 1 mol = 52 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

CH₄ = 1.25 mol, O₂ = 0.625 mol. Oxygen is insufficient and is limiting.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Na = 2 mol, H₂O = 3 mol. Na is limiting. H₂ = 1 mol = 2 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

O₂ is limiting. H₂O formed = (2/3) × 2 = 1.33 mol.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

33. The concept that even a large excess of one reactant cannot produce more product than dictated by the other reactant is a consequence of the

A. Law of Conservation of Mass
B. Principle of the limiting reactant
C. Kinetic theory of gases
D. Law of Multiple Proportions

The limiting reactant determines the maximum yield regardless of excess reactant.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

32. In the reaction P₄ + 6Cl₂ → 4PCl₃, a mixture of 62 g of P₄ and 213 g of Cl₂ is taken. The limiting reactant is

A. Phosphorus
B. Chlorine
C. Both are stoichiometric
D. Phosphorus trichloride

P₄ = 0.5 mol and Cl₂ = 3 mol. Required Cl₂ = 3 mol. Both react completely.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Fe = 2 mol, H₂O = 2 mol. Water is limiting. Fe₃O₄ = 0.5 mol. Mass = 0.5 × 232 = 116 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

30. A key characteristic of the limiting reactant is that its amount determines the

A. Rate constant of the reaction
B. Activation energy of the reaction
C. Theoretical yield of the product
D. Equilibrium constant of the reaction

The limiting reactant determines the maximum amount of product that can be formed.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026
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