Practice Questions

Among the following statements, the most appropriate explanation for using mole ratios instead of mass ratios in balanced equations is

A. Chemical equations represent reacting particles rather than masses
B. All reactants have equal molar masses
C. Mole ratios change with temperature
D. Mass is not conserved during reactions

The coefficients in a balanced chemical equation represent the relative numbers of molecules or moles participating in the reaction. Masses depend on molar masses and are not directly represented by the coefficients. Concept tested: Significance of mole ratios in stoichiometry.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the reaction Ca + 2HCl → CaCl₂ + H₂, complete reaction of 3 moles of calcium requires

A. 2 moles of HCl
B. 3 moles of HCl
C. 6 moles of HCl
D. 9 moles of HCl

The balanced equation shows that 1 mole of Ca reacts with 2 moles of HCl. Therefore, 3 moles of Ca require 6 moles of HCl. Concept tested: Mole ratio application.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Concerning stoichiometric calculations, the limiting reagent is identified because it

A. Produces the smallest amount of product
B. Has the greatest molar mass
C. Is always present in the smallest mass
D. Remains completely unreacted

The limiting reagent is the reactant that is consumed first and determines the maximum amount of product formed. It is not necessarily the reactant with the smallest mass or highest molar mass. Concept tested: Limiting reagent concept.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

The molar mass of CO₂ is 44 g mol⁻¹. Therefore, 44 g corresponds to exactly one mole. Concept tested: Mass-to-mole conversion.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During a chemical calculation, 0.25 mole of methane contains

A. 1.51 × 10²³ molecules
B. 3.01 × 10²³ molecules
C. 6.02 × 10²³ molecules
D. 7.53 × 10²² molecules

One mole contains 6.02 × 10²³ molecules. Therefore, 0.25 mole contains one-fourth of this value, equal to 1.51 × 10²³ molecules. Concept tested: Representative particles.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Regarding the balanced equation 2K + 2H₂O → 2KOH + H₂, complete reaction of 8 moles of potassium produces

A. 2 moles of H₂
B. 4 moles of H₂
C. 6 moles of H₂
D. 8 moles of H₂

The equation shows that 2 moles of K produce 1 mole of H₂. Therefore, 8 moles of K produce 4 moles of hydrogen gas. Concept tested: Stoichiometric mole ratio.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Under standard conditions, 89.6 L of oxygen gas corresponds to

A. 2 moles
B. 3 moles
C. 4 moles
D. 5 moles

At STP, one mole of gas occupies 22.4 L. Therefore, 89.6 ÷ 22.4 = 4 moles. Concept tested: Gas volume to mole conversion.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the decomposition reaction 2HgO → 2Hg + O₂, complete decomposition of 8 moles of HgO produces

A. 2 moles of O₂
B. 4 moles of O₂
C. 6 moles of O₂
D. 8 moles of O₂

According to the balanced equation, 2 moles of HgO produce 1 mole of O₂. Therefore, 8 moles of HgO produce 4 moles of O₂. Concept tested: Stoichiometric calculations.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Concerning Avogadro’s number, 3 moles of carbon dioxide contain

A. 6.02 × 10²³ molecules
B. 1.20 × 10²⁴ molecules
C. 1.81 × 10²⁴ molecules
D. 3.01 × 10²³ molecules

Three moles contain 3 × 6.02 × 10²³ = 1.81 × 10²⁴ molecules. The other values represent fewer moles. Concept tested: Mole-to-particles conversion.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the reaction 2Al + 3Cl₂ → 2AlCl₃, complete reaction of 6 moles of chlorine gas produces

A. 2 moles of AlCl₃
B. 4 moles of AlCl₃
C. 6 moles of AlCl₃
D. 9 moles of AlCl₃

The balanced equation shows that 3 moles of Cl₂ produce 2 moles of AlCl₃. Therefore, 6 moles of Cl₂ produce 4 moles of AlCl₃. Concept tested: Mole ratio from a balanced equation.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026
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