Practice Questions

The limiting reactant determines the theoretical yield.

O₂ limits the reaction. Only 2 mol P₄ react, leaving 2 mol P₄.

The reactants are present in the exact stoichiometric ratio.

It is the reactant consumed first, stopping the reaction.

CaCO₃ = 0.1 mol, HCl = 0.274 mol. Since only 0.2 mol HCl is required, CaCO₃ is limiting.

One mole of Fe₂O₃ reacts with 3 mol CO to produce 2 mol Fe = 112 g.

H₂ is limiting. NH₃ formed = (2/3) × 4 = 2.67 mol.

Al = 2 mol, Cl₂ = 1 mol. Two moles Al require 3 mol Cl₂, so chlorine is limiting.

The reaction is 1:1. Two moles of O₂ produce only 2 moles of CO₂.

8 mol O₂ require only 6.4 mol NH₃. Therefore, NH₃ remains in excess by 1.6 mol.