Practice Questions

Hydrogen is the limiting reactant because 9 moles are required. Six moles of hydrogen produce four moles of ammonia.

Na₂SO₄ contains two sodium ions per formula unit. Therefore, 0.5 mole gives one mole of Na⁺ ions.

Glucose contains six carbon atoms per molecule. Therefore, 0.5 mole of carbon atoms corresponds to 0.5 ÷ 6 = 0.083 mole of glucose.

Each NH₃ molecule contains three hydrogen atoms; therefore one mole of NH₃ contains three moles of hydrogen atoms.

Forty-eight grams of magnesium equal two moles, producing two moles of MgO. The mass becomes 80 g.

One mole occupies 22.4 dm³ at STP, so two moles occupy 44.8 dm³.

One mole of nitrogen produces two moles of nitrogen dioxide. Therefore, 0.5 mole yields one mole.

One mole always contains 6.022 × 10²³ elementary particles.

The balanced equation directly provides the ratio.

This represents 0.5 mole of water. Half of 18 g equals 9 g.