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Practice Questions

Regarding the reaction CaCO₃ → CaO + CO₂, thermal decomposition of 2.5 moles of calcium carbonate produces

A. 1.25 moles of CO₂
B. 2.5 moles of CO₂
C. 5.0 moles of CO₂
D. 7.5 moles of CO₂

The balanced equation indicates a 1 : 1 mole ratio between CaCO₃ and CO₂. Therefore, 2.5 moles of CaCO₃ yield 2.5 moles of CO₂. Concept tested: Stoichiometric mole calculations.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the reaction 2Na + Cl₂ → 2NaCl, complete reaction of 5 moles of sodium produces

A. 2.5 moles of NaCl
B. 5 moles of NaCl
C. 7.5 moles of NaCl
D. 10 moles of NaCl

The balanced equation shows a 2 : 2 ratio between Na and NaCl, which simplifies to 1 : 1. Therefore, 5 moles of Na produce 5 moles of NaCl. Concept tested: Mole ratio from a balanced equation.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Among the following statements, the most appropriate reason balanced chemical equations are essential in stoichiometric calculations is

A. They provide the physical states of reactants
B. They provide the exact mole relationships among reactants and products
C. They indicate the reaction temperature
D. They determine the reaction rate

Stoichiometric calculations depend on the coefficients of a balanced equation because they represent mole ratios. Physical states, temperature, and reaction rate are not sufficient for quantitative calculations. Concept tested: Importance of balanced equations in stoichiometry.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the reaction 2H₂ + O₂ → 2H₂O, complete reaction of 44.8 L of oxygen at STP produces

A. 22.4 L of H₂O(g)
B. 44.8 L of H₂O(g)
C. 89.6 L of H₂O(g)
D. 67.2 L of H₂O(g)

At the same conditions of temperature and pressure, gas volumes follow mole ratios. One volume of O₂ produces two volumes of gaseous H₂O. Thus, 44.8 L O₂ forms 89.6 L H₂O(g). Concept tested: Gas volume ratios at STP.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Regarding representative particles, one mole of sodium atoms contains

A. 6.02 × 10²³ atoms
B. 6.02 × 10²³ molecules
C. 3.01 × 10²³ atoms
D. 1.20 × 10²⁴ atoms

Sodium is an element consisting of atoms, so one mole contains Avogadro's number of atoms, not molecules. Concept tested: Representative particles.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the decomposition reaction 2KClO₃ → 2KCl + 3O₂, decomposition of 4 moles of KClO₃ produces

A. 3 moles of O₂
B. 4 moles of O₂
C. 5 moles of O₂
D. 6 moles of O₂

According to the balanced equation, 2 moles of KClO₃ produce 3 moles of O₂. Therefore, 4 moles produce 6 moles of O₂. Concept tested: Stoichiometric calculations using balanced equations.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the combustion reaction CH₄ + 2O₂ → CO₂ + 2H₂O, complete combustion of 3 moles of methane produces

A. 2 moles of CO₂
B. 3 moles of CO₂
C. 4 moles of CO₂
D. 6 moles of CO₂

The balanced equation shows a 1 : 1 mole ratio between CH₄ and CO₂. Thus, 3 moles of methane produce 3 moles of carbon dioxide. Concept tested: Mole ratio application.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Under standard conditions, one mole of an ideal gas occupies

A. 11.2 L
B. 22.4 L
C. 44.8 L
D. 24.0 L

At STP (0°C and 1 atm), one mole of any ideal gas occupies 22.4 L. Values like 24.0 L apply approximately at room temperature, not STP. Concept tested: Molar volume of gases.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During a chemical calculation, 18 g of water corresponds to

A. 0.5 mole
B. 1 mole
C. 2 moles
D. 18 moles

The molar mass of H₂O is 18 g mol⁻¹. Therefore, 18 g represents exactly one mole. Concept tested: Mass-mole relationship.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

Concerning Avogadro’s number, one mole of any substance contains

A. 3.01 × 10²³ particles
B. 6.02 × 10²² particles
C. 6.02 × 10²³ particles
D. 1.00 × 10²³ particles

Avogadro's number is 6.02 × 10²³ representative particles per mole. The other values are incorrect multiples or fractions. Concept tested: Avogadro's constant.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During the reaction N₂ + 3H₂ → 2NH₃, complete reaction of 2 moles of nitrogen requires

A. 3 moles of H₂
B. 4 moles of H₂
C. 6 moles of H₂
D. 2 moles of H₂

From the equation, 1 mole of N₂ reacts with 3 moles of H₂. Therefore, 2 moles of N₂ require 6 moles of H₂. Concept tested: Stoichiometric mole calculations.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

The coefficients in a balanced equation represent mole ratios. Here, 2 moles of H₂ react with 1 mole of O₂. The other ratios do not match the balanced equation. Concept tested: Mole ratio from a balanced equation.

nmdcat.online Chemistry NMDCAT MCQs
Jul 13, 2026

During cellular metabolism, feedback inhibition is considered an efficient regulatory mechanism because it

A. Conserves energy by preventing unnecessary product synthesis
B. Permanently blocks all enzyme activity
C. Increases the rate of every metabolic pathway
D. Converts metabolic products into enzymes

Feedback inhibition stops metabolic pathways once sufficient end product has accumulated, conserving cellular energy and raw materials. Concept tested: Biological importance of feedback inhibition.

nmdcat.online BIO NMDCAT
Jul 13, 2026

Regarding enzyme inhibitors used in medicine, selective inhibition is preferred because it

A. Targets disease-causing pathways with minimal effects on normal cells
B. Permanently destroys all enzymes in the body
C. Prevents the formation of every metabolic product
D. Eliminates all enzyme-substrate interactions

Selective enzyme inhibitors reduce disease processes while minimizing damage to healthy tissues, making them effective therapeutic agents. Concept tested: Clinical application of enzyme inhibitors.

nmdcat.online BIO NMDCAT
Jul 13, 2026

The experimental observation indicates that both substrate binding and enzyme concentration remain unchanged, yet the reaction rate decreases. The most appropriate explanation is

A. Catalytic activity has been reduced by a non-competitive inhibitor
B. The substrate has been completely consumed
C. Additional active sites have been formed
D. The enzyme has become a coenzyme

Non-competitive inhibitors reduce catalytic efficiency without necessarily affecting substrate binding. Concept tested: Interpretation of enzyme inhibition experiments.

nmdcat.online BIO NMDCAT
Jul 13, 2026

During poisoning by heavy metals, severe metabolic disturbances occur because heavy metals

A. Irreversibly inactivate essential enzymes
B. Increase substrate concentration in cells
C. Convert enzymes into coenzymes
D. Stimulate ATP production

Heavy metals bind strongly to functional groups of enzymes, permanently reducing their catalytic activity and disrupting metabolism. Concept tested: Toxicological effects of heavy metals.

nmdcat.online BIO NMDCAT
Jul 13, 2026

Among the following statements, enzyme inhibition is most beneficial to living organisms when it

A. Regulates metabolic pathways according to cellular needs
B. Stops all metabolic reactions permanently
C. Prevents enzyme synthesis throughout life
D. Eliminates the requirement for cofactors

Enzyme inhibitors are essential regulators that maintain metabolic balance and cellular homeostasis. The other options would be harmful to living organisms. Concept tested: Physiological significance of inhibition.

nmdcat.online BIO NMDCAT
Jul 13, 2026

During an experiment, the inhibitor binds at a site other than the active site without affecting substrate binding directly. The reaction rate decreases because

A. The enzyme undergoes a conformational change
B. The substrate is chemically destroyed
C. The active site is permanently removed
D. The enzyme becomes a product

Non-competitive inhibitors alter the enzyme's shape, reducing catalytic efficiency without directly blocking substrate binding. Concept tested: Allosteric inhibition.

nmdcat.online BIO NMDCAT
Jul 13, 2026

Concerning metabolic pathways, the end product commonly inhibits

A. The first enzyme of the pathway
B. The last enzyme of the pathway
C. Every enzyme equally
D. Only enzymes outside the pathway

In feedback inhibition, the final product usually inhibits the first committed enzyme, preventing unnecessary synthesis of additional product. Concept tested: Mechanism of feedback inhibition.

nmdcat.online BIO NMDCAT
Jul 13, 2026
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