Practice Questions

Stoichiometric mixture. H₂ produced = 0.3 mol. Volume = 6.72 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

74. The mole ratio from the balanced equation is used to calculate the amount of excess reactant consumed by the

A. Limiting reactant
B. Product formed
C. Catalyst present
D. Initial mixture volume

The limiting reactant determines how much of the excess reactant is used.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Carbon is limiting. CH₄ = 1.5 mol. Mass = 24 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Stoichiometric mixture. Titanium formed = 1 mol = 48 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

71. The theoretical yield of a product is calculated based on the

A. Amount of the excess reactant
B. Average mass of reactants
C. Amount of the limiting reactant
D. Amount of catalyst

The limiting reactant determines the maximum product obtainable.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

HCl is limiting. CaCl₂ formed = 0.5 mol. Mass = 55.5 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

N₂ is the limiting reactant and is completely consumed.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

SO₂ is limiting. SO₃ formed = 2 mol. Mass = 160 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

One mole X requires 3 mol Y. Only 2 mol Y are available.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

O₂ is limiting. P₂O₅ formed = 0.8 mol.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026
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