Practice Questions

Stoichiometric mixture. Na₂CO₃ = 1 mol. Mass = 106 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

O₂ is limiting. CO₂ = 3.2 mol. Volume = 71.68 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

63. The concept of limiting and excess reactants is a direct application of the Law of

A. Conservation of Mass and Definite Proportions
B. Multiple Proportions
C. Reciprocal Proportions
D. Gaseous Volumes

Stoichiometry is based on these fundamental chemical laws.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Potassium is limiting. KOH formed = 1 mol. Mass = 56 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Na₂CO₃ is limiting. CO₂ formed = 0.5 mol. Mass = 22 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Stoichiometric mixture. SO₂ = 1 mol. Mass = 64 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

59. A key step in solving a limiting reactant problem is converting all masses into moles because balanced equations provide

A. Mass ratios
B. Volume ratios only
C. Mole ratios
D. Energy changes

Stoichiometric coefficients always represent mole ratios.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

0.2 mol Pb(NO₃)₂ produces 0.5 mol gases. Volume = 11.2 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

BaCl₂ is limiting. BaSO₄ formed = 0.3 mol. Mass = 69.9 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

10 mol A require 20 mol B. Only 10 mol B are available, so B is limiting.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026
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