Practice Questions

Stoichiometric mixture. Na₂CO₃ = 1 mol. Mass = 106 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

O₂ is limiting. CO₂ = 3.2 mol. Volume = 71.68 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

63. The concept of limiting and excess reactants is a direct application of the Law of

A. Conservation of Mass and Definite Proportions ✓
B. Multiple Proportions
C. Reciprocal Proportions
D. Gaseous Volumes

Stoichiometry is based on these fundamental chemical laws.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Potassium is limiting. KOH formed = 1 mol. Mass = 56 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Na₂CO₃ is limiting. CO₂ formed = 0.5 mol. Mass = 22 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

Stoichiometric mixture. SO₂ = 1 mol. Mass = 64 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

59. A key step in solving a limiting reactant problem is converting all masses into moles because balanced equations provide

A. Mass ratios
B. Volume ratios only
C. Mole ratios ✓
D. Energy changes

Stoichiometric coefficients always represent mole ratios.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

0.2 mol Pb(NO₃)₂ produces 0.5 mol gases. Volume = 11.2 dm³.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

BaCl₂ is limiting. BaSO₄ formed = 0.3 mol. Mass = 69.9 g.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026

10 mol A require 20 mol B. Only 10 mol B are available, so B is limiting.

nmdcat.online Chemistry NMDCAT MCQs
Jul 2, 2026
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