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The glycosidic bond in a disaccharide is formed between the anomeric carbon of one sugar and a hydroxyl carbon of another, releasing a water molecule. In the nomenclature, the bond is named by specifying the anomeric configuration (α or β) of the first sugar and the carbon numbers involved. Thus, the name “α-1,4 glycosidic bond” indicates that the

A. First sugar is an aldose, and the second is a ketose
B. Anomeric carbon in the α-configuration of the first sugar is linked to the C4 of the second sugar ✓
C. Bond is in the fourth position of the ring
D. Sugar chain is four carbons long

The notation specifies the configuration (α) of the anomeric carbon (C-1) of the first sugar, and the carbon (C-4) of the second sugar to which it is linked. This precise nomenclature is essential for describing the specific, biologically active structure of an oligo- or polysaccharide.

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Jun 27, 2026

A critical structural feature of the disaccharide cellobiose, a product of cellulose degradation, is that it consists of two glucose units linked by a

A. β-1,4 glycosidic bond ✓
B. α-1,4 glycosidic bond
C. α-1,2 glycosidic bond
D. β-1,6 glycosidic bond

Cellobiose is the repeating disaccharide unit of cellulose and is formed by partial hydrolysis. It consists of two β-D-glucose molecules linked by a β-1,4 glycosidic bond. It is an isomer of maltose, which has an α-1,4 linkage.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The reason that a freshly prepared solution of α-D-glucose has a different optical rotation from an equilibrium mixture is that mutarotation has not yet established the equilibrium between the α and β anomers. The open-chain form is a necessary intermediate in this process, and its concentration at equilibrium is extremely low (less than 0.1%) because

A. It is highly unstable and is rapidly oxidized to an acid
B. The cyclic hemiacetal form is significantly more thermodynamically stable than the open-chain aldehyde form ✓
C. It precipitates out of solution due to its low solubility
D. It is immediately fermented by airborne bacteria

The cyclic form, a hemiacetal, is much lower in energy than the free aldehyde. The equilibrium thus lies heavily on the side of the cyclic forms. The open form is a high-energy, transient intermediate that exists only briefly to allow anomeric interconversion.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The size of the ring is determined by which hydroxyl attacks the carbonyl. Reaction with the C4-OH forms a five-membered ring (furanose). Reaction with the C5-OH forms a six-membered ring (pyranose). The pyranose form is favored for most aldohexoses due to lower steric strain.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The primary difference between a homopolysaccharide and a heteropolysaccharide lies in the

A. Type of glycosidic bond linking the monomer units
B. Identity of the monosaccharide monomer units that make up the polymer ✓
C. Degree of branching within the polymer chain
D. Molecular weight and solubility of the final polymer

A homopolysaccharide is composed of a single type of monosaccharide monomer (e.g., starch, cellulose, glycogen are all made of glucose). A heteropolysaccharide contains two or more different types of monosaccharide units (e.g., peptidoglycan, agar, hyaluronic acid).

nmdcat.online BIO NMDCAT
Jun 27, 2026

The molecule heparan sulfate is a glycosaminoglycan that functions as an anticoagulant by binding to and activating antithrombin III. Its anticoagulant activity is directly dependent on a specific, highly sulfated pentasaccharide sequence within the polymer. This mechanism of action is an example of

A. A structural carbohydrate acting as a rigid scaffold
B. A carbohydrate specifically acting as a regulatory or signaling molecule ✓
C. A storage carbohydrate being mobilized for energy
D. A carbohydrate functioning as a molecular chaperone

This is a classic example of a complex carbohydrate playing a specific biological regulatory role. The unique sequence in heparan sulfate binds to antithrombin III, inducing a conformational change that dramatically increases its affinity for thrombin and Factor Xa, preventing blood clotting.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The only significant difference between the structures of amylose and cellulose is the configuration at the anomeric carbon, but this single difference results in amylose being a flexible helix and cellulose being a rigid, straight chain. The structural basis for this is that the α-1,4 linkage in amylose allows for a bent, kinked conformation, whereas the β-1,4 linkage forces each glucose unit to

A. Rotate 180 degrees relative to its neighbor, creating a straight, extended chain ✓
B. Form a five-membered furanose ring instead of a pyranose ring
C. Lose its ability to form intra-chain hydrogen bonds
D. Exist in an open-chain form rather than a ring form

In cellulose, every glucose residue is flipped 180° relative to the next to accommodate the β-1,4 linkage. This creates a straight, ribbon-like structure with cellobiose as the repeating unit. In amylose, the α-1,4 linkage does not require this flip, causing the chain to adopt a helical twist.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In β-D-glucose, the anomeric -OH on C1 is equatorial. In the chair form, bulky substituents in equatorial positions have more space and experience less steric strain (1,3-diaxial interactions), making this conformation thermodynamically more stable than the α-anomer (axial -OH).

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the industrial production of ethanol from starch, the process of saccharification refers to the

A. Fermentation of glucose to ethanol by yeast
B. Hydrolysis of starch into fermentable sugars by acid or amylolytic enzymes ✓
C. Distillation of ethanol from the fermentation broth
D. Purification of the final product by molecular sieves

Saccharification is the step where the polysaccharide starch is chemically or enzymatically hydrolyzed into simple sugars (glucose and maltose). These sugars then serve as substrates for the subsequent fermentation by microorganisms to produce ethanol.

nmdcat.online BIO NMDCAT
Jun 27, 2026

O-linked glycosylation involves the formation of a glycosidic bond between the anomeric carbon of a sugar (often N-acetylgalactosamine) and the hydroxyl group of a serine or threonine residue in the protein. N-linked glycosylation links to the amide nitrogen of asparagine.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The formation of a glycosidic bond between a monosaccharide’s anomeric carbon and an alcohol group of another molecule (e.g., methanol) yields a glycoside. A glycoside is inherently non-reducing because

A. The glycosidic bond is in the β-configuration
B. The alcohol group prevents the ring from opening by locking the anomeric carbon in an acetal/ketal form ✓
C. The methanol molecule denatures the sugar
D. The reaction increases the molecular weight of the sugar, preventing reduction

The anomeric carbon in a glycoside is part of an acetal (or ketal) functional group, which is stable and cannot open to the free carbonyl form in a neutral/basic aqueous solution. Since no free carbonyl can form, the sugar cannot act as a reducing agent.

nmdcat.online BIO NMDCAT
Jun 27, 2026

S. mutans produces glucosyltransferases that specifically use sucrose to synthesize sticky, water-insoluble glucan polymers (dental plaque). The sucrose is then fermented to lactic acid within this plaque, causing localized demineralization of tooth enamel.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The blue color formed in the iodine test for starch is due to a charge-transfer complex. This test will yield a negative result (no blue color) with a sample of glycogen because glycogen’s

A. Lower molecular weight prevents complex formation
B. Much shorter average chain length of its outer branches forms an unstable, reddish-brown complex ✓
C. Absence of α-1,4 linkages prevents iodine binding
D. Covalent linkage to proteins blocks the iodine-binding sites

The iodine test requires a helix of sufficient length to stabilize the polyiodide chain. Glycogen's highly branched structure means its α-1,4 helical segments are very short. With iodine, it yields a reddish-brown color (not blue-black), which can be easily confused with a negative test if not careful.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the solubility of monosaccharides, they are highly soluble in water due to their

A. Non-polar hydrocarbon chains
B. High molecular weight
C. Numerous hydroxyl groups that form hydrogen bonds with water ✓
D. Furanose ring structure

Each monosaccharide has several polar -OH groups that can participate in hydrogen bonding with water molecules. This strong interaction (adhesion) overcomes the sugar-sugar interactions and allows the sugars to dissolve readily in water.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The D/L designation is fixed by the configuration of the highest-numbered chiral center (C-5 in hexoses). The α and β anomers are defined specifically by the orientation of the hydroxyl group on the newly formed chiral center, the anomeric carbon (C-1 in aldoses), relative to the ring.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Amylopectin is a homopolymer of D-glucose. Complete hydrolysis with strong acid will break all the α-1,4 and α-1,6 glycosidic bonds, yielding only D-glucose monomers as the final product.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The phenomenon of “resistant starch” refers to starch and starch degradation products that

A. Are completely hydrolyzed in the mouth by salivary amylase
B. Escape digestion in the small intestine and are fermented in the large intestine ✓
C. Inhibit the action of pancreatic lipase
D. Are covalently bonded to cellulose, making them indigestible

Resistant starch is physically inaccessible or structurally resistant to pancreatic amylases. It passes to the colon, where it acts similarly to soluble fiber, being fermented by gut microbiota, producing beneficial short-chain fatty acids.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The glycosidic linkage of the polysaccharide agar, extracted from red algae, is composed of D-galactose and an unusual L-galactose derivative. The primary biological application of agar in a laboratory setting is based on its property of

A. Being a highly digestible nutrient for bacterial growth
B. Forming a stable, inert gel that solidifies at a temperature below the growth optimum of most microorganisms ✓
C. Inhibiting the growth of fungi while allowing bacterial growth
D. Acting as a reducing agent in biochemical assays

Agar melts at ~85°C and solidifies at ~32-40°C. Once gelled, it remains solid at typical incubation temperatures (e.g., 37°C) and is resistant to degradation by most microorganisms, making it an ideal, inert solidifying agent for culture media.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A comparison of the open-chain forms of glucose and fructose reveals that they are

A. Enantiomers
B. Structural isomers ✓
C. Diastereomers
D. Anomers

Both have the same molecular formula (C₆H₁₂O₆), but different functional groups—glucose is an aldehyde (aldose) and fructose is a ketone (ketose). This difference in the connectivity of atoms makes them structural (constitutional) isomers.

nmdcat.online BIO NMDCAT
Jun 27, 2026
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