MCQs

11262 questions found

Practice Questions

The high heat of vaporization of water is critical for thermoregulation in mammals because

A. It requires a large amount of heat to be absorbed from the environment to convert liquid to gas ✓
B. It releases a massive amount of heat into the body when sweat evaporates
C. It prevents any water loss from the body surface during exercise
D. It ensures that the body's internal temperature is always lower than the external air temperature

When sweat evaporates, the phase change from liquid to gas requires a large amount of heat energy (latent heat of vaporization). This heat is absorbed from the skin's surface, effectively cooling the body. The cooling is due to heat removal, not heat release.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the context of water as a metabolite, its role in photosynthesis involves

A. Being oxidized to O₂ after providing electrons to Photosystem II ✓
B. Absorbing light energy to excite chlorophyll electrons
C. Acting as the final electron acceptor in the electron transport chain
D. Forming a structural scaffold for the thylakoid membrane

During the light-dependent reactions, water undergoes photolysis. Water is split (oxidized) by the oxygen-evolving complex, providing replacement electrons to P680 (Photosystem II) and releasing protons (H⁺) and molecular oxygen (O₂) as a byproduct.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The cohesive property of water is primarily responsible for the

A. Ability of water to dissolve non-polar gases like oxygen
B. Formation of a hydration shell around sodium and chloride ions
C. Transport of water and dissolved minerals in the xylem of plants under tension ✓
D. Activation of enzymes that require a dehydrating environment

Transpiration pull creates negative pressure in xylem. Due to strong cohesion (H-bonds between water molecules), the continuous water column is pulled upwards. Adhesion to xylem walls also assists, but the tensile strength of the water column is a direct result of cohesion.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A significant consequence of water’s density anomaly, where its solid form is less dense than its liquid form, is that

A. Ice sinks to the bottom, allowing water to freeze from the bottom up
B. Aquatic life cannot survive in sub-zero climates
C. Ice forms an insulating layer on the surface, preventing bodies of water from freezing solid ✓
D. The specific heat of water decreases as it freezes

At 4°C, water is densest. Below 4°C, it expands, and ice (0°C) is ~9% less dense, so it floats. This surface ice layer insulates the liquid water below, maintaining a temperature above freezing and allowing aquatic life to survive winter.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The property of water that enables small insects to move across the surface of a pond is

A. High viscosity
B. High surface tension due to cohesion ✓
C. Low density compared to the insect's exoskeleton
D. Low specific heat of the water surface

Cohesion creates a strong network of hydrogen bonds at the water-air interface, generating surface tension. This film-like layer is resistant to external force, supporting objects denser than water if they do not break the surface layer.

nmdcat.online BIO NMDCAT
Jun 27, 2026

During the digestion of starch into glucose, the specific function of water is to

A. Provide a medium for the emulsification of starch granules
B. Cleave the glycosidic bonds through a hydrolytic reaction ✓
C. Phosphorylate glucose to trap it inside the cell
D. Bind to the active site of amylase as a competitive inhibitor

Enzymatic digestion of starch is a hydrolysis reaction. Water molecules are used to break the α-1,4 glycosidic bonds between glucose monomers. The H from water attaches to one glucose, and the OH attaches to the adjacent glucose.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The high specific heat capacity of water is biologically significant because it

A. Allows water to absorb large amounts of heat with a minimal rise in its own temperature, stabilizing cellular temperatures ✓
B. Enables water to reach boiling point rapidly for thermoregulation through sweating
C. Promotes rapid temperature fluctuations in aquatic ecosystems
D. Reduces the hydrogen bonding capacity of water molecules

Water's high specific heat (1 cal/g°C) means it absorbs considerable heat energy for a small temperature increase. This property, due to hydrogen bonding, provides thermal stability to organisms and large bodies of water, protecting protoplasm from drastic temperature shifts.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the process of hydrolysis in biological systems, the role of water is to

A. Act as a catalyst to speed up the reaction without being consumed
B. Provide the energy required to break a covalent bond
C. Serve as a reactant that is split to break a covalent bond in a larger molecule ✓
D. Remove heat generated during the cleavage of a polymer

Hydrolysis (hydro = water, lysis = splitting) uses water as a reactant. The bond in the polymer is broken, and the components of water (H and OH) are added to the resulting monomers. Enzymes catalyze this reaction, but water is a substrate, not a catalyst.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In living organisms, the exceptional ability of water to act as a universal solvent for polar substances is primarily attributed to

A. Its low molecular weight
B. Its high specific heat capacity
C. Its molecular polarity and capacity to form hydrogen bonds ✓
D. Its low density in the solid state

Water dissolves polar and ionic solutes by forming hydration shells. The partial charges of water molecules interact electrostatically with ions or polar groups, and hydrogen bonding stabilizes the dissolved state. Low molecular weight and high specific heat are separate properties.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The polarity of a water molecule is a direct consequence of

A. The linear arrangement of its two hydrogen atoms
B. The equal sharing of electrons between oxygen and hydrogen
C. The bent geometry and the higher electronegativity of the oxygen atom ✓
D. The presence of strong ionic bonds holding the atoms together

Water has a V-shaped bent geometry (104.5° bond angle). Oxygen's higher electronegativity pulls shared electrons closer, creating a partial negative charge (δ⁻) on oxygen and partial positive charges (δ⁺) on hydrogens. The bonds are polar covalent, not ionic, and the unequal sharing creates a molecular dipole.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The function of the 5′ cap and 3′ poly-A tail added to eukaryotic mRNA is to

A. Serve as the start and stop signals for translation of the coding sequence
B. Facilitate the splicing of exons and the removal of introns
C. Protect the mRNA molecule from exonucleolytic degradation in the cytoplasm ✓
D. Provide the template for the synthesis of the protein's primary sequence

The 5' cap and the 3' poly-A tail are not translated. Their primary roles are to increase the stability of the mRNA by protecting its ends from ribonucleases, and to facilitate the initiation of translation by interacting with translation initiation factors.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The use of Benedict’s test on a solution of sucrose yields a negative result (no color change) because sucrose

A. Is a monosaccharide, not a disaccharide
B. Has a free aldehyde group that is locked in the furanose ring
C. Lacks a free anomeric carbon capable of reducing Cu²⁺, as both are involved in the glycosidic bond ✓
D. Is a non-reducing sugar that can only be detected by the iodine test

The glycosidic bond in sucrose is formed between the anomeric carbon (C1) of glucose and the anomeric carbon (C2) of fructose. Since neither carbonyl group is free to open into an aldehyde or ketone form, sucrose cannot reduce Cu²⁺ and is thus a non-reducing sugar.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In competitive inhibition, the apparent Km (Michaelis constant) of the enzyme for its substrate is

A. Unchanged
B. Decreased
C. Increased ✓
D. Equal to Vmax

A competitive inhibitor competes for the active site, effectively making it harder for the enzyme to bind its substrate. More substrate is required to reach half the maximum velocity. Therefore, the apparent Km (substrate concentration at 1/2 Vmax) is increased in the presence of a competitive inhibitor.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The main structural difference between amylose and amylopectin, the two components of starch, is that amylopectin has a

A. Linear, unbranched structure of glucose linked by α-1,4 bonds
B. Highly branched structure due to the presence of α-1,6-glycosidic bonds ✓
C. Structure composed of β-1,4-linked glucose units only
D. Lower molecular weight and solubility compared to amylose

Amylose is a linear polymer of glucose with α-1,4 linkages. Amylopectin is a much larger, branched polymer that has both α-1,4 linkages in the straight chain and α-1,6 glycosidic bonds at the branch points approximately every 24-30 glucose units.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Kinases are a class of transferase enzymes that catalyze the transfer of a γ-phosphate group from a high-energy donor molecule like ATP to a specific substrate. Protein kinases phosphorylate specific serine, threonine, or tyrosine residues on target enzymes, regulating their activity. Phosphatases reverse this.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the structure of an antibody molecule, the region responsible for the vast diversity that allows binding to a specific antigen is the

A. Constant region of the heavy chain
B. Variable region at the amino-terminal end of both the light and heavy chains ✓
C. Transmembrane anchoring domain
D. The carbohydrate moiety attached to the Fc region

The amino-terminal ends of both the light (VL) and heavy (VH) chains form the antigen-binding site. These variable domains have highly diverse amino acid sequences from one antibody clone to another, creating a unique 3D surface that is specific for a single epitope.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The reason that an increase in the concentration of a competitive inhibitor does not change the maximum velocity (Vmax) of an enzymatic reaction is that

A. The inhibitor reduces the turnover number of the enzyme
B. The inhibitor permanently denatures a fraction of the enzyme population
C. The inhibitor's binding can be overcome by sufficiently increasing the substrate concentration ✓
D. The inhibitor binds only to the enzyme-substrate complex, not the free enzyme

The definition of competitive inhibition is a "competition" for the active site. At a high enough concentration, the substrate out-competes the inhibitor for the active site, so all enzyme molecules can still bind substrate and reach Vmax. The apparent Km is increased, but Vmax is ultimately unchanged.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The allosteric regulation of an enzyme differs from competitive and non-competitive inhibition in that allosteric modulators

A. Always bind to the active site of the enzyme
B. Bind to a site distinct from the active site, leading to a conformational change ✓
C. Are always irreversible inhibitors of the enzyme
D. Compete with the substrate for binding at the catalytic site

Allosteric regulation is mediated by modulator molecules that bind to a site (allosteric site) physically distinct from the active site. This binding causes a conformational change that can either increase (allosteric activator) or decrease (allosteric inhibitor) the activity of the enzyme at its active site.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In covalent catalysis, a powerful nucleophilic R-group in the active site (e.g., the -SH of cysteine or -OH of serine) forms a transient covalent bond with the substrate. This acyl-enzyme intermediate is then resolved by another step, releasing the product and regenerating the free enzyme.

nmdcat.online BIO NMDCAT
Jun 27, 2026
Page 172 of 593
Jump to:

🏆 Top Contributors

  • N

    nmdcat.online

    11260 MCQs

  • N

    NMDCAT.ONLINE

    1 MCQ

  • G

    GULABsb

    1 MCQ

Categories

View all →