Practice Questions

The catalytic triad in serine proteases consists of Asp, His, and Ser. This arrangement allows histidine to act as

A. A competitive inhibitor
B. An irreversible covalent cross-linker
C. A general acid-base catalyst, shuttling protons between serine and the substrate
D. A metal-chelating group

The triad allows histidine to act as a powerful general base catalyst, abstracting a proton from the serine hydroxyl group to make it a nucleophile.

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For an enzymatic reaction with a fixed enzyme concentration, the relationship between substrate concentration and initial reaction velocity is described by a

A. Sigmoidal curve, indicating cooperativity
B. Straight line, indicating a first-order reaction
C. Hyperbolic curve, showing saturation kinetics as per the Michaelis-Menten model
D. Parabolic curve

Non-allosteric enzymes follow Michaelis-Menten kinetics, where the plot of V₀ vs. [S] is a rectangular hyperbola: first-order at low [S] and zero-order at high [S].

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In an uninhibited, reversible, enzyme-catalyzed reaction, the sole function of the enzyme is to

A. Shift the point of equilibrium towards the products
B. Decrease the standard free energy change (ΔG°)
C. Reduce the magnitude of the activation energy
D. Increase the concentration of substrate molecules

An enzyme accelerates both forward and reverse reactions equally by lowering activation energy without changing the equilibrium point or free energy.

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The most appropriate explanation for the high turnover number of carbonic anhydrase is that

A. It binds its substrate, CO₂, with very low affinity
B. The activation energy for the reaction without the enzyme is negligible
C. The reaction rate is essentially diffusion-limited
D. It is an allosteric enzyme

Carbonic anhydrase is so efficient that the rate-limiting step is the diffusion of the substrate into the active site.

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Ligases catalyze the joining of two molecules with the concomitant hydrolysis of a high-energy phosphate bond, such as ATP.

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Among the following, the correct statement regarding the conversion of an apoenzyme to a holoenzyme is that it

A. Requires the removal of a prosthetic group by dialysis
B. Is a reversible process involving the binding of a specific cofactor
C. Involves an irreversible proteolytic cleavage
D. Results in a complete change in the substrate specificity

An inactive apoenzyme becomes an active holoenzyme upon binding its required cofactor, a non-covalent, reversible process essential for regulation.

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The structure responsible for the catalytic power and specificity of an enzyme is the

A. Coenzyme binding domain
B. Allosteric regulatory site
C. Signal peptide sequence at the N-terminus
D. Active site pocket formed by tertiary folding

The active site, a 3D cleft formed by folding, provides the unique chemical and physical environment responsible for an enzyme's power and specificity.

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The reaction exhibiting an optimal pH that reflects the ionization state of active site residues, rather than a global denaturation effect, suggests that

A. The enzyme is a ribozyme
B. Catalysis depends critically on the protonation state of specific amino acid R-groups
C. The enzyme has an absolute requirement for a metal ion
D. The substrate can only bind when it is in a fully uncharged state

Bell-shaped pH-activity profiles often reflect the ionization of catalytic residues that must be in a specific protonation state to function as acid/base catalysts.

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In a coupled assay system, enzyme X generates a product that is the substrate for enzyme Y. The activity of enzyme X is measured by the rate of product formation by enzyme Y, which is a direct measure of

A. The Km of enzyme Y for its substrate
B. The activity of enzyme X
C. The Vmax of enzyme Y in isolation
D. The affinity of enzyme X for a cofactor

In a coupled assay where enzyme Y and its substrates are in excess, the rate of product formation by Y is proportional to the rate at which X provides its substrate.

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The primary effect of a non-competitive inhibitor on an enzyme-catalyzed reaction is to

A. Compete directly with the substrate for occupation of the active site
B. Reduce the Vmax of the reaction without significantly altering the Km for the substrate
C. Increase the apparent Km for the substrate while leaving Vmax unchanged
D. Irreversibly modify the active site serine residue

A non-competitive inhibitor binds to a separate site, forming a non-productive complex that lowers the concentration of functional enzyme, thus reducing Vmax.

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