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BIO NMDCAT

1895 questions found

Subcategories

📁 ACELLULAR LIFR 20 📁 AIDS and HIV Infection 50 📁 and nerve impulse Reflexes and reflex arc 0 📁 Arthritis 0 📁 axon 0 📁 BIOENERGETICS 0 📁 Biological Importance of Water 95 📁 BIOLOGICAL MOLECULES 126 📁 Biotechnology 0 📁 Biotechnology and Health Care 0 📁 Blood Vessels 0 📁 Brain 25 📁 Carbohydrates 100 📁 Cardiac cycle and phases of Heartbeat 0 📁 cell body 0 📁 cell membrane 70 📁 CELL STRUCTURE & FUNCTION 100 📁 Chromosomes 76 📁 Circulation 0 📁 Concept of Evolution 50 📁 Conjugated molecules 100 📁 COORDINATION & CONTROL NERVOUS & CHEMICAL COORDINATION 0 📁 Cytoplasmic Organelles 75 📁 Darwinism 50 📁 dendrites 0 📁 DIVERSITY AMONG ANTMALS (THE KTNGDOM ANIMALIA) 0 📁 ENZYMES 108 📁 EVOLUTION 0 📁 Factors that Affect the Rate of Enzyme Reactions 60 📁 Form and Function in Plants 0 📁 Gene linkage and crossing over 0 📁 Homeostasis (kidney specifically) 0 📁 Homeostasis Mainly Kidney Portion nmdcat etea 0 📁 Human Heart 0 📁 Human Reproductive system 0 📁 Human Reproductive system-Menstrual cycle 0 📁 Human skeleton 40 📁 INHERITANCE 0 📁 Inhibitors 40 📁 Joints 0 📁 Lamarckism 50 📁 Lipids 45 📁 lmmunity 0 📁 Lymphatic system 0 📁 Mendel's laws of Inheritance 0 📁 Menstrual cycle 0 📁 Mode of Enzyme Action 60 📁 Muscle contraction 0 📁 Muscles 70 📁 myelin sheath 0 📁 Neurons 41 📁 PROKARYOTES (KTNGDOM MONERA) 0 📁 Prokaryotic and Eukaryotic cell 0 📁 Proteins 95 📁 Receptors 40 📁 REPRODUCTION 0 📁 Respiration 15 📁 Respiratory system 0 📁 Ribonucleic acid (RNA) 100 📁 Sexually transmitted diseases 50 📁 Skeletal muscles 0 📁 Specific Defense Mechanism 0 📁 Structure of DNA 98 📁 SUPPORT & MOVEMENT 0 📁 Viruses 46 📁 X-linked Recessive inheritance 0

Practice Questions

The catalytic efficiency of an enzyme is significantly reduced by a non-competitive inhibitor because it

A. Competes for the same active site as the substrate
B. Denatures the enzyme by breaking all peptide bonds
C. Binds to an allosteric site and changes the active site's conformation ✓
D. Removes the cofactor from the holoenzyme irreversibly

A non-competitive inhibitor binds to a site different from the active site (an allosteric site). This binding alters the three-dimensional shape of the enzyme, including the active site, so the substrate can no longer bind effectively, regardless of substrate concentration.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the structure of DNA, the strict pairing of adenine with thymine and guanine with cytosine is essential for

A. Forming a strong sugar-phosphate backbone
B. Maintaining a uniform helix diameter and accurate replication ✓
C. Binding RNA polymerase during transcription
D. Providing the energy for polynucleotide synthesis

The specific base pairing (A-T with 2 H-bonds, G-C with 3 H-bonds) between a purine and a pyrimidine ensures the two DNA strands are equidistant apart, creating a uniform diameter. This complementarity is also the molecular logic for semi-conservative replication.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Concerning the classification of lipids, terpenoids are synthesized from the basic building block of

A. Glycerol and fatty acids
B. Amino acids
C. Isoprene units ✓
D. Sphingosine

Terpenoids (or terpenes), including steroids, carotenoids, and natural rubber, are a large class of lipids built from multiple isoprene units (C5H8). This distinguishes their biosynthetic origin from acylglycerols, which are fatty acid esters.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The hydrolysis of sucrose results in a mixture of glucose and fructose, which is chemically referred to as an

A. Invert sugar ✓
B. Non-reducing sugar
C. Aldohexose
D. Ketohexose

Sucrose is dextrorotatory, but upon hydrolysis, the resulting mixture of glucose (dextrorotatory) and fructose (strongly levorotatory) makes the overall solution levorotatory. This change in optical rotation is called inversion, and the product is called invert sugar.

nmdcat.online BIO NMDCAT
Jun 27, 2026

An enzyme’s specificity for a single substrate can be best explained by the model that compares the active site to a

A. Fluid mosaic
B. Induced spring
C. Lock and key ✓
D. Open channel

The lock-and-key model proposes a rigid active site that is perfectly complementary only to a specific substrate, ensuring high specificity. The induced fit model expands on this, adding flexibility, but the lock-and-key concept directly explains absolute specificity.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Pepsin is a gastric enzyme that has adapted to function in the highly acidic environment of the stomach, where HCl is present. Therefore, its optimum pH is strongly acidic (around 1.5-2.0), unlike enzymes like trypsin which function in the alkaline small intestine (pH ~8.0).

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the structure of a nucleotide, the nitrogenous base is attached to the pentose sugar at the

A. 1' carbon via a glycosidic bond ✓
B. 3' carbon via a phosphodiester bond
C. 5' carbon via a phosphate bond
D. 2' carbon via a hydrogen bond

The covalent bond linking the nitrogenous base (purine or pyrimidine) to the 1' carbon of the pentose sugar (ribose or deoxyribose) is an N-glycosidic bond. The phosphate group is linked to the 5' carbon.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The property of glucose that makes it a reducing sugar is its ability to

A. Form glycosidic bonds with fructose
B. Polymerize into long, branched chains
C. Donate electrons to other compounds in a redox reaction ✓
D. Dissolve readily in plasma membrane lipids

A reducing sugar has a free aldehyde or ketone group that can reduce (donate electrons to) another compound, such as Cu²⁺ to Cu⁺ in Benedict's test. Glycosidic bond formation masks this group. Polymerization is a separate property, and glucose is lipid-insoluble.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The covalent linkage in the sugar-phosphate backbone of nucleic acids is a phosphodiester bond. It is formed between the 3' carbon of one sugar and the 5' phosphate group of the adjacent sugar. Glycosidic bonds link sugar to base, and peptide bonds link amino acids.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A characteristic feature that distinguishes phospholipids from triglycerides is the replacement of one fatty acid with a

A. Glycerol molecule
B. Phosphate-containing group ✓
C. Cholesterol molecule
D. Saturated hydrocarbon chain

A triglyceride has glycerol esterified to three fatty acids. A phospholipid is a modified triglyceride where one fatty acid chain is replaced by a highly polar phosphate group, which is often further linked to a nitrogenous compound, creating an amphipathic molecule.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The insolubility of lipids in water is fundamentally attributed to the presence of

A. A high proportion of oxygen atoms creating polar bonds
B. Long, non-polar hydrocarbon chains in their structure ✓
C. Charged phosphate groups in their polar heads
D. Multiple hydroxyl groups forming hydrogen bonds

The bulk of a lipid molecule, like a fatty acid or triglyceride, consists of long hydrocarbon chains (C-H bonds). These bonds are non-polar and hydrophobic, repelling interaction with polar water molecules and leading to insolubility.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Among the following amino acids, the one classified as non-essential for human adults is

A. Lysine
B. Phenylalanine
C. Alanine ✓
D. Valine

Non-essential amino acids are those the human body can synthesize de novo. Alanine can be produced from pyruvate. Lysine, phenylalanine, and valine are essential amino acids that cannot be synthesized and must be obtained from the diet.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the secondary structure of proteins, the β-pleated sheet is primarily stabilized by

A. Disulfide bridges between cysteine amino acids
B. Hydrogen bonds between the carbonyl and amino groups of the backbone ✓
C. Hydrophobic interactions between non-polar R-groups
D. Ionic bonds between oppositely charged R-groups

Both α-helices and β-pleated sheets are secondary structures stabilized by regular hydrogen bonding between the backbone atoms (the C=O of one amino acid and the N-H of another). R-group interactions define the tertiary structure. Disulfide bridges are covalent, not hydrogen, bonds.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the tertiary structure of a globular protein, the folding pattern is determined by the

A. Repetitive hydrogen bonding along the polypeptide backbone
B. Linear sequence of nucleotides in the corresponding gene
C. Interactions among the variable side chains (R-groups) of the amino acids ✓
D. Condensation of the protein with a carbohydrate moiety

Tertiary structure is the overall 3D conformation of a single polypeptide chain, driven by interactions between the R-groups. This includes hydrophobic interactions, ionic bonds, hydrogen bonds, and disulfide bridges. The backbone H-bonding defines secondary structure.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A mutation in a gene results in a single amino acid substitution in a hemoglobin protein, causing sickle cell anemia. This alteration directly affects the protein’s

A. Primary structure
B. Secondary structure
C. Tertiary structure
D. All of the structural levels mentioned ✓

Changing one amino acid (primary structure) can disrupt the local folding (secondary), which in turn alters the overall 3D shape (tertiary) and its ability to bind with other subunits (quaternary). Thus, all higher levels of structure are ultimately dependent on the primary sequence.

nmdcat.online BIO NMDCAT
Jun 27, 2026

When a protein is subjected to extreme pH or high temperature, the disruption of its functional three-dimensional shape is primarily due to the breakage of

A. Peptide bonds
B. Weak interactions like hydrogen and ionic bonds ✓
C. Glycosidic linkages
D. Phosphodiester bonds

Denaturation unfolds a protein by disrupting the non-covalent interactions (hydrogen bonds, ionic bonds, hydrophobic interactions) that stabilize secondary, tertiary, and quaternary structures. The primary structure's covalent peptide bonds usually remain intact.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A significant increase in the proportion of unsaturated fatty acids in a phospholipid bilayer would result in

A. Decreased membrane fluidity
B. Increased membrane fluidity ✓
C. Formation of a solid monolayer
D. Inhibition of all membrane transport

Unsaturated fatty acids contain kinks due to double bonds, preventing tight packing of the hydrocarbon tails. This increased space between lipids makes the membrane more fluid and permeable compared to a membrane rich in straight-chained saturated fatty acids.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The most appropriate description of an enzyme’s active site is a

A. Permanent, rigid groove on the enzyme's surface
B. Flexible, three-dimensional cleft formed by the folding of the polypeptide chain ✓
C. Sequence of amino acids at the N-terminus of the enzyme
D. Non-protein component essential for catalysis

The active site is a 3D pocket formed by amino acid residues brought together via the protein's tertiary folding. It is complementary to the substrate's shape and chemistry, and models like "induced fit" show it is flexible, not rigid.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the function of waxes in living organisms, their primary role is related to

A. Long-term energy storage in adipose tissue
B. Waterproofing and protection in both plants and animals ✓
C. Encoding hereditary information
D. Catalyzing metabolic reactions

Waxes are hydrophobic lipids that form impermeable coatings. In plants (e.g., cutin on leaves) and animals (e.g., sebum on skin/fur), their main function is to prevent water loss and provide protection, not energy storage, which is the role of fats and oils.

nmdcat.online BIO NMDCAT
Jun 27, 2026
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