MCQs

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Practice Questions

The catalytic efficiency of an enzyme is significantly reduced by a non-competitive inhibitor because it

A. Competes for the same active site as the substrate
B. Denatures the enzyme by breaking all peptide bonds
C. Binds to an allosteric site and changes the active site's conformation
D. Removes the cofactor from the holoenzyme irreversibly

A non-competitive inhibitor binds to a site different from the active site (an allosteric site). This binding alters the three-dimensional shape of the enzyme, including the active site, so the substrate can no longer bind effectively, regardless of substrate concentration.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A mutation in a gene results in a single amino acid substitution in a hemoglobin protein, causing sickle cell anemia. This alteration directly affects the protein’s

A. Primary structure
B. Secondary structure
C. Tertiary structure
D. All of the structural levels mentioned

Changing one amino acid (primary structure) can disrupt the local folding (secondary), which in turn alters the overall 3D shape (tertiary) and its ability to bind with other subunits (quaternary). Thus, all higher levels of structure are ultimately dependent on the primary sequence.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the tertiary structure of a globular protein, the folding pattern is determined by the

A. Repetitive hydrogen bonding along the polypeptide backbone
B. Linear sequence of nucleotides in the corresponding gene
C. Interactions among the variable side chains (R-groups) of the amino acids
D. Condensation of the protein with a carbohydrate moiety

Tertiary structure is the overall 3D conformation of a single polypeptide chain, driven by interactions between the R-groups. This includes hydrophobic interactions, ionic bonds, hydrogen bonds, and disulfide bridges. The backbone H-bonding defines secondary structure.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the secondary structure of proteins, the β-pleated sheet is primarily stabilized by

A. Disulfide bridges between cysteine amino acids
B. Hydrogen bonds between the carbonyl and amino groups of the backbone
C. Hydrophobic interactions between non-polar R-groups
D. Ionic bonds between oppositely charged R-groups

Both α-helices and β-pleated sheets are secondary structures stabilized by regular hydrogen bonding between the backbone atoms (the C=O of one amino acid and the N-H of another). R-group interactions define the tertiary structure. Disulfide bridges are covalent, not hydrogen, bonds.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Among the following amino acids, the one classified as non-essential for human adults is

A. Lysine
B. Phenylalanine
C. Alanine
D. Valine

Non-essential amino acids are those the human body can synthesize de novo. Alanine can be produced from pyruvate. Lysine, phenylalanine, and valine are essential amino acids that cannot be synthesized and must be obtained from the diet.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The insolubility of lipids in water is fundamentally attributed to the presence of

A. A high proportion of oxygen atoms creating polar bonds
B. Long, non-polar hydrocarbon chains in their structure
C. Charged phosphate groups in their polar heads
D. Multiple hydroxyl groups forming hydrogen bonds

The bulk of a lipid molecule, like a fatty acid or triglyceride, consists of long hydrocarbon chains (C-H bonds). These bonds are non-polar and hydrophobic, repelling interaction with polar water molecules and leading to insolubility.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A characteristic feature that distinguishes phospholipids from triglycerides is the replacement of one fatty acid with a

A. Glycerol molecule
B. Phosphate-containing group
C. Cholesterol molecule
D. Saturated hydrocarbon chain

A triglyceride has glycerol esterified to three fatty acids. A phospholipid is a modified triglyceride where one fatty acid chain is replaced by a highly polar phosphate group, which is often further linked to a nitrogenous compound, creating an amphipathic molecule.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The covalent linkage in the sugar-phosphate backbone of nucleic acids is a phosphodiester bond. It is formed between the 3' carbon of one sugar and the 5' phosphate group of the adjacent sugar. Glycosidic bonds link sugar to base, and peptide bonds link amino acids.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The property of glucose that makes it a reducing sugar is its ability to

A. Form glycosidic bonds with fructose
B. Polymerize into long, branched chains
C. Donate electrons to other compounds in a redox reaction
D. Dissolve readily in plasma membrane lipids

A reducing sugar has a free aldehyde or ketone group that can reduce (donate electrons to) another compound, such as Cu²⁺ to Cu⁺ in Benedict's test. Glycosidic bond formation masks this group. Polymerization is a separate property, and glucose is lipid-insoluble.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The most abundant biological molecule found in the living world is

A. Protein
B. Lipid
C. Carbohydrate
D. Water

While organic molecules are the focus of discussion, water is the most abundant molecule constituting 70-90% of the cell's mass. Among organic biological molecules, carbohydrates like cellulose are the most abundant, but the question specifies "in the living world," making water the correct overarching answer.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Chitin is a linear polysaccharide of N-acetylglucosamine monomers, linked by β-glycosidic bonds, providing structural support in arthropod exoskeletons and fungal cell walls. Cellulose is the structural polymer in plant cell walls. Starch and glycogen are energy storage molecules.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A competitive inhibitor reduces the rate of an enzyme-catalyzed reaction by

A. Binding to the allosteric site and altering the enzyme's shape
B. Binding to the enzyme-substrate complex irreversibly
C. Mimicking the substrate and occupying the active site
D. Denaturing the enzyme protein at its active site

A competitive inhibitor structurally resembles the substrate and competes for binding at the enzyme's active site. This effect can be overcome by increasing substrate concentration. It does not bind to the allosteric site or permanently alter the enzyme.

nmdcat.online BIO NMDCAT
Jun 27, 2026

In the induced fit model of enzyme-substrate interaction, the binding of the substrate to the enzyme causes

A. The enzyme to completely change its primary structure
B. The active site to undergo a conformational change for a tighter fit
C. The substrate to permanently break down before binding
D. The enzyme to be consumed in the reaction

Unlike the rigid lock-and-key model, the induced fit model proposes that the active site is flexible. The initial substrate binding induces a conformational change in the enzyme, molding the active site into a precise complementary shape around the substrate.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Regarding the function of waxes in living organisms, their primary role is related to

A. Long-term energy storage in adipose tissue
B. Waterproofing and protection in both plants and animals
C. Encoding hereditary information
D. Catalyzing metabolic reactions

Waxes are hydrophobic lipids that form impermeable coatings. In plants (e.g., cutin on leaves) and animals (e.g., sebum on skin/fur), their main function is to prevent water loss and provide protection, not energy storage, which is the role of fats and oils.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The most appropriate description of an enzyme’s active site is a

A. Permanent, rigid groove on the enzyme's surface
B. Flexible, three-dimensional cleft formed by the folding of the polypeptide chain
C. Sequence of amino acids at the N-terminus of the enzyme
D. Non-protein component essential for catalysis

The active site is a 3D pocket formed by amino acid residues brought together via the protein's tertiary folding. It is complementary to the substrate's shape and chemistry, and models like "induced fit" show it is flexible, not rigid.

nmdcat.online BIO NMDCAT
Jun 27, 2026

A significant increase in the proportion of unsaturated fatty acids in a phospholipid bilayer would result in

A. Decreased membrane fluidity
B. Increased membrane fluidity
C. Formation of a solid monolayer
D. Inhibition of all membrane transport

Unsaturated fatty acids contain kinks due to double bonds, preventing tight packing of the hydrocarbon tails. This increased space between lipids makes the membrane more fluid and permeable compared to a membrane rich in straight-chained saturated fatty acids.

nmdcat.online BIO NMDCAT
Jun 27, 2026

When a protein is subjected to extreme pH or high temperature, the disruption of its functional three-dimensional shape is primarily due to the breakage of

A. Peptide bonds
B. Weak interactions like hydrogen and ionic bonds
C. Glycosidic linkages
D. Phosphodiester bonds

Denaturation unfolds a protein by disrupting the non-covalent interactions (hydrogen bonds, ionic bonds, hydrophobic interactions) that stabilize secondary, tertiary, and quaternary structures. The primary structure's covalent peptide bonds usually remain intact.

nmdcat.online BIO NMDCAT
Jun 27, 2026

The fluid mosaic model of the cell membrane describes the arrangement of phospholipids as a

A. Single layer with proteins only on the outer surface
B. Rigid bilayer with proteins spanning the interior
C. Fluid bilayer with proteins embedded or attached
D. Solid monolayer with carbohydrates coating the exterior

The model proposes a dynamic, fluid phospholipid bilayer where individual lipid molecules can move laterally. Proteins are not just on the surface but are integral or peripheral, creating a "mosaic" pattern that floats within the fluid lipid sea.

nmdcat.online BIO NMDCAT
Jun 27, 2026

Concerning the prosthetic group of a conjugated protein, its removal invariably leads to the formation of a

A. Simple protein only
B. Holoprotein
C. Apoenzyme without its cofactor
D. Amino acid pool

A conjugated protein (holoprotein) consists of a protein part (apoprotein) and a non-protein part (prosthetic group). If the prosthetic group is a cofactor and the protein is an enzyme, its removal yields an inactive apoenzyme. The term specifically relates to the loss of the non-protein component.

nmdcat.online BIO NMDCAT
Jun 27, 2026
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