∫(x³ – 2x + 5) dx = ? x⁴/4 – x² + 5x + C x³ – x² + 5x x⁴/4 – 2x² + 5x x³/3 – x² + 5x Calculus (Basic)
If f(x) = 2x³ – 3x² + x – 5, f'(x) = ? 6x² – 6x + 1 6x² – 3x + 1 3x² – 3x + 1 6x² – 3x – 5 Calculus (Basic)